How to display multiple rows in one records in sql

Syntax :
select
   Col1,
        listagg(COL2, ',') within group (order by COL2) as COL2
From TABLE
Group By
   Col1


Example
Create Table Test_Transpose(Ids Number , Val Number);
Insert Into Test_Transpose Values (1, 11);
Insert Into Test_Transpose Values (1, 12);
Insert Into Test_Transpose Values (1, 13);
Insert Into Test_Transpose Values (1, 14);
Insert Into Test_Transpose Values (1, 15);
Insert Into Test_Transpose Values (2, 21);
Insert Into Test_Transpose Values (2, 22);
Insert Into Test_Transpose Values (2, 23);
Insert Into Test_Transpose Values (2, 24);
Insert Into Test_Transpose Values (2, 25);
Commit;
/

Select * From  Test_Transpose;
Output

IDS	VAL
1	11
1	12
1	13
1	14
1	15
2	21
2	22
2	23
2	24
2	25

Select
   IDS,
        listagg(VAL, ',') within group (order by VAL) as VAL
From Test_Transpose
Group By
   Ids
Output :

IDS	VAL
1	11,12,13,14,15
2	21,22,23,24,25

TO_DATE Format

TO_DATE Format Masks
Format	Returns
D	Day of the week
DD	Day of the month
DDD	Numerical day of the year, 1 ~ 365 (366 for Leap years)
DAY	Full textual representation of the day, i.e. "Monday", "Tuesday", "Wednesday"
DY	Day in three letters, i.e. "MON", "TUE", "FRI"
W	Week of the month
WW	Week of the year
MM	Month in two digits, i.e. 01 = Jan, 02 = Feb,...12 = -Dec
MON	Month in three characters, i.e. "Jan", "Feb", "Apr"
MONTH	Full textual representation of the Month, i.e. "January", "February", "April"
RM	Month in Roman Characters (I-XII, I-Jan, II-Feb, ... XII-Dec)
Q	Quarter of the Month
YY	Last two digits of the year.
YYYY	Full year
YEAR	Year in words like "Nineteen Eighty Seven"
HH	Hours in 12 hour format
HH12	Hours in 12 hour format
HH24	Hours in 24 hour format ("military time")
MI	Minutes
SS	Seconds
FF	Fractional Seconds
SSSSS	Milliseconds
J	Julian Day i.e Days since 1st-Jan-4712BC to till-date
RR	If the year is less than 50 then Oracle considers the year as a 21st century date. If the year is greater than 50 then Oracle considers the year to be in the 20th century.